2.3x^2+2x-3=0

Solution for 2.3x^2+2x-3=0 equation:

2.3x^2+2x-3=0

a = 2.3; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·2.3·(-3)
Δ = 31.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{31.6}}{2*2.3}=\frac{-2-\sqrt{31.6}}{4.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{31.6}}{2*2.3}=\frac{-2+\sqrt{31.6}}{4.6}
$